… For these spaces, it is also shown that ρ is an R/N-epimorphism if and only if it is a CR-epimorphism.
Along the way, we look at some regular rings naturally related to C(X), namely T(X), …

… a ring R is a ring S for which there is a homomorphism 11: R ~ S which is both a monomorphism
and an epimorphism in the category of rings. … P(R) is the minimal regular subring of Q(R) …

… Let R be right noetherian satisfying generic regularity and S an abelian regular ring. If a:
R + S is an epimorphism in the category of rings then a factors uniquely through …

… epimorphism in the category of all Rings and ring homomorphisms by proving that any pair
of ring … Let a: R —+S be an epimorphism fi-om a regular unital ring R to a unital ring S in the …

… rings a product of ring epimorphisms (in the categorical meaning of “epimorphism”) is not
necessarily an epimorphism (… If R → S is a ring epimorphism with S regular then reg deg R S ≤ …

… Thus in investigating the epimorphisms from a homomorphically closed class of rings, we
are essentially … We shall prove that all epimorphisms (in ft ) from (von Neumann) regular …

… An element of A is regular if it is not a zero-divisor. Let K denote the (classical) localization
of A at all regular elements, that is, the total ring of fractions of A. A finitely generated A-module …

… case - a ring imple and dominant, but not regular is con- [ 1, p7] has called a ring R
epimorphismfinal if every ring epimorphism … Such a ring must be simple, and a simple regular ring …

… regular ring, and let A* be the Boolean ring of idempotents … we prove that the endomorphism
ring of an ideal of R is regular, and that the homological dimension of an ideal is equal … ring. …

… We show that every injective ring epimorphism λ : R → S with the property that TorR … From
Corollary 5.6(2) we infer that for every set U of simple regular right R-modules, the right R-…