following. If G is a Kr+ 1-free graph on at least r+ 1 vertices and m edges, then by subdividing an edge. Both conditions are best possible. We conclude this paper with some open problems.
Bollobás and Nikiforov (J. Combin. Theory Ser. B.97 (2007) 859–865) conjectured the following. If G is a Kr+1-free graph on at least r+1 vertices and m edges, then by subdividing an edge. Both conditions are best possible. We conclude this paper with some open problems.