divisible by 2 into an inner product space E, the functional inequality¶¶\(\Vert2f (x)+ 2f (y)-f (xy^{-1})\Vert\leq\Vert f (xy)\Vert\\\(x, y\in G)\)¶ implies the parallelogram equation¶\(f (xy)+ f (xy^{-1})-2f (x)-2f (y)= 0\\\(x, y\in G)\).
Summary
In this paper it is proved that, for a function mapping from an abelian group G divisible by 2 into an inner product space E, the functional inequality¶¶\(\Vert2f (x)+ 2f (y)-f (xy^{-1})\Vert\leq\Vert f (xy)\Vert\\\(x, y\in G)\)¶ implies the parallelogram equation¶\(f (xy)+ f (xy^{-1})-2f (x)-2f (y)= 0\\\(x, y\in G)\).